Let us consider the linear integro-differential equation
$$
\begin{cases}
\displaystyle \displaystyle\cos(x)\frac{d^2}{dx^2}y - \sin(x^3-x)\frac{d}{d}y+\exp({\frac{x^2}{2}})y - \cosh(x)\int_{0}^{x}\sin(x-4t)y(t)dt
\\\hfill \displaystyle+\sinh(x)\int_{0}^{1}\cos(t^2-x)y(t)dt = \exp({\sin(x^3-x)+x^2})\\
y(0)=1,\ y(1)=0
\end{cases}.
$$ The approximate solution on Tau Toolbox:
The approximate tau solution achieves the machine precision:
Example 2
Let us consider the linear integro-differential equation
$$
\begin{cases}
\displaystyle \frac{d}{dx}y+2y+5\int_{0}^{x}y(t)dt=1\\
y(0)=0
\end{cases}.
$$ The approximate solution on Tau Toolbox:
The approximate tau solution achieves the machine precision: