Let us consider the linear system of differential equations with polynomial coefficients
$$
\begin{cases}
\displaystyle y_2-\frac{d}{dx}y_1=0\\
\displaystyle y_3-\frac{d}{dx}y_2=0\\
\displaystyle (x^2+1)\frac{d}{dx}y_3-(x^2+3x)\frac{d}{dx}y_2+5xy_2-5y_1=60x^2-10\\
y_1(-1)=4,\ y_2(1)=2,\ y_3(0)=0
\end{cases}.
$$ The approximate solution on Tau Toolbox:
The approximate tau solution achieves the machine precision:
Example 2
Let us consider the linear system of differential equations with non-polynomial coefficients
$$
\begin{cases}
\displaystyle \cos(x)\frac{d}{dx}y_1-(x^2-3x^4)y_2+3\frac{d}{dx}y_3 = \cos(x)^2-\cos(\exp(x))(- 3x^4+x^2)-6\sin(2x)\\
\displaystyle \sin(x)\frac{d}{dx}y_1+\frac{d}{dx}y_2-y_3 =\sin(x)\cos(x)-\cos(2x)-\sin(\exp(x))\exp(x)\\
\displaystyle -y_1+\exp(x)y_2+x^3\frac{d}{dx}y_3 =\cos(\exp(x))\exp(x) - \sin(x) - 2x^3\sin(2x)\\
y_1(-\pi)=0,\ y_2(0)=\cos(1),\ y_3(\pi)=1
\end{cases}
$$ The approximate solution on Tau Toolbox:
The approximate tau solution achieves the machine precision: